3p^2+35p-12=90

Solution for 3p^2+35p-12=90 equation:

3p^2+35p-12=90

We move all terms to the left:

3p^2+35p-12-(90)=0

We add all the numbers together, and all the variables

3p^2+35p-102=0

a = 3; b = 35; c = -102;
Δ = b2-4ac
Δ = 352-4·3·(-102)
Δ = 2449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-\sqrt{2449}}{2*3}=\frac{-35-\sqrt{2449}}{6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+\sqrt{2449}}{2*3}=\frac{-35+\sqrt{2449}}{6}
$